Component | Symbol |
---|---|

Wire Conductor | |

Resistor | |

Battery |

## Parallel-Circuits

A parallel circuit has two or more components connected across each other. Since this allows the current to flow along multiple paths, the current value will often be different on each branch. On the other hand, the applied voltage will be the same across all parallel branches of the circuit.

Figure 2 above shows a parallel circuit. The current leaving the negative terminal of the battery divides with some current passing through the *R _{1}* branch and some passing through the

*R*branch of the circuit before returning to the positive terminal of the battery. Knowing the values for

_{2}*R*and

_{1}*R*plus knowing there is a 30 volt drop across both resistors allows you to calculate the current passing through each resistor using Ohm's Law.

_{2}`I _{1}` =

`V`/

`R`= (30 volts)/(5Ω) = 6 amperes

_{1}`I _{2}` =

`V`/

`R`= (30 volts)/(10Ω) = 3 amperes

_{2}The total equivalent resistance of `N` number of resistors in parallel can be calculated using the following formula:

`1/`

+ … + 1/`R _{total}` = 1/

`R`+ 1/

_{1}`R`+ 1/

_{2}`R`

_{3}`R`

_{N}When there are only two resistors in parallel, there is a simpler formula to determine the equivalent resistance:

In the case of figure 2, the equivalent resistance of the circuit would be:

`1/`

or `R _{total}` = 1/

`R`+ 1/

_{1}`R`= 1/(5 Ω) + 1/(10 Ω) = 3/(10 Ω)

_{2}`R`_{total} = 3⅓ ohms

Having the total voltage and now the total equivalent resistance, you can calculate the total current using Ohm's Law:

which is equal to the sum of the two current drops, `I _{total}` =

`V`/

`R`= (30 volts) / (3⅓ ohms) = 9 amperes

_{total}`I`and

_{1}`I`. How about that?

_{2}