## Series-Parallel-Circuits

Most real world circuits are not pure series or pure parallel but are a combination to the two. Figure 3 shows a typical circuit that has both series and parallel components. After leaving the negative terminal of the battery, all current must flow through resistor *R _{1}*. This is the series portion of the circuit. After exiting

*R*, the current has two possible paths:

_{1}*R*or

_{2}*R*. This is the parallel portion.

_{3}## Simplify

Analysis of a series-parallel circuit involves simplifying the circuit. The first step for the circuit above would be to determine the equivalent resistance for the parallel branches of *R _{2}* and

*R*. Using the formula for parallel resistances, their

_{3}*R*would be:

_{equiv}`R _{equiv}` = (

`R`x

_{2}`R`) / (

_{3}`R`+

_{2}`R`) = (10 Ω x 5 Ω) /(10 Ω + 5 Ω) = (50 Ω) / (15 Ω) = 3⅓ ohms.

_{3}The circuit has now been reduced to the series only circuit shown in figure 4. The next step is to use the series formula for resistance to determine the total resistance of the circuit.

.`R _{total}` =

`R`+

_{1}`R`= 5 Ω + 3⅓ Ω = 8⅓ ohms

_{equiv}You now have reduced the circuit to a single resistance as shown in figure 5.